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1808 United States presidential election in Ohio

Main article: 1808 United States presidential election
1808 United States presidential election in Ohio
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Nominee James Madison Charles C. Pinckney James Monroe
Party Democratic-Republican Federalist Tertium quids
Home state Virginia South Carolina Virginia
Running mate George Clinton Rufus King none
Electoral vote 3 0 0
Popular vote 3,645 1,174 1,174
Percentage 60.82% 19.59% 19.59%
President before election

Thomas Jefferson
Democratic-Republican

Elected President

James Madison
Democratic-Republican

The 1808 United States presidential election in Ohio took place as part of the 1808 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president.

James Madison, the nominee of the governing Democratic-Republican Party, defeated Federalist Party challenger Charles C. Pinckney and fellow Democratic-Republican James Monroe, who ran as the candidate of the Tertium quids, by 2,471 votes (41.23%). Monroe would later succeed Madison as the fifth president of the United States in 1817.[1]

Results

1808 United States presidential election in Ohio[2]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison 3,645 60.82% 3
Federalist Charles Cotesworth Pinckney 1,174 19.59 0
Tertium quids James Monroe 1,174 19.59 0
Totals 5,993 100.0% 3

References

  1. ^ Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.
  2. ^ Lampi, Philip. "Ohio 1808 Electoral College". A New Nation Votes. Tufts University. Retrieved July 11, 2021.


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