1928 tennis event results
First-seeded Helen Wills defeated Eileen Bennett 6–1, 6–2 in the final to win the women's singles tennis title at the 1928 French Championships.[1] The draw consisted of 37 players of which 8 were seeded.
Seeds
The seeded players are listed below. Helen Wills is the champion; others show the round in which they were eliminated.
- Helen Wills (champion)
- Suzanne Devé (second round)
- Kea Bouman (semifinals)
- Daphne Akhurst (quarterfinals)
- Elisabeth Macready (second round)
- Lilly De Alvarez (first round)
- Marguerite Bordes (third round)
- Eileen Bennett (finalist)
Draw
Key
Finals
Earlier rounds
Section 1
Section 2
Section 3
Section 4
References
- ^ Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York]: New Chapter Press. p. 393. ISBN 978-0942257700.
External links