1928 United States presidential election in Delaware

1928 United States presidential election in Delaware
County Results Hoover 50-60% 60-70%
President before election; Calvin Coolidge; Republican	Elected President ; Herbert Hoover; Republican

The 1928 United States presidential election in Delaware took place on November 6, 1928. All contemporary 48 states were part of the 1928 United States presidential election. State voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by Republican former Secretary of Commerce Herbert Hoover of California, who was running against Democratic Governor of New York Alfred E. Smith. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith's running mate was Senator Joseph Taylor Robinson of Arkansas.

Hoover won with a majority of 65.03% of the vote to Smith's 34.60%, a margin of 30.43%. Socialist candidate Norman Thomas finished a distant third, with 0.31%. Hoover’s performance is the best by any presidential candidate in Delaware, surpassing its nearest rival from Barack Obama in 2008 by 3.12%.^[1] In this election, Delaware voted 13% to the right of the nation at-large.^[2]

Results

1928 United States presidential election in Delaware^[3]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Herbert Hoover	68,860	65.03%	3
	Democratic	Alfred E. Smith	36,643	34.60%	0
	Socialist	Norman Thomas	329	0.31%	0
	Communist	William Z. Foster	56	0.06%	0
Totals			105,891	100.0%	3

Results by county

County	Herbert Hoover Republican		Al Smith Democratic		Various candidates Other parties		Margin		Total votes cast
County	#	%	#	%	#	%	#	%	Total votes cast
Kent	8,335	59.16%	5,727	40.65%	27	0.19%	2,608	18.51%	14,089
New Castle	47,641	67.66%	22,464	31.90%	307	0.44%	25,177	35.76%	70,412
Sussex	12,884	64.10%	7,163	35.64%	54	0.26%	5,721	28.46%	20,101
Totals	68,860	65.03%	36,643	34.60%	388	0.37%	32,217	30.43%	105,891