2004 ATP Buenos Aires – Doubles

Doubles
2004 ATP Buenos Aires
Final
Champions	Lucas Arnold Mariano Hood
Runners-up	Federico Browne Diego Veronelli
Score	7–5, 6–7(2–7), 6–4
Events
Singles Doubles
← 2003 · ATP Buenos Aires · 2005 →

Mariano Hood and Sebastián Prieto were the defending champions but they competed with different partners that year, Hood with Lucas Arnold and Prieto with Martín García.

García and Prieto lost in the first round to Juan Ignacio Chela and Nicolás Massú.

Arnold and Hood won in the final 7–5, 6–7^(2–7), 6–4 against Federico Browne and Diego Veronelli.

	First round							Quarterfinals							Semifinals							Final
	1	L Arnold M Hood	3	6	7
		M Fyrstenberg M Matkowski	6	3	5			1	L Arnold M Hood	77	6
		A Calleri G Cañas	6	6					A Calleri G Cañas	60	2
		D Ferrer R Ramírez Hidalgo	1	2											1	L Arnold M Hood	w/o
	4	M García S Prieto	3	4												J I Chela N Massú
		J I Chela N Massú	6	6					J I Chela N Massú	7	6
	WC	G Coria J Mónaco	6	6				WC	G Coria J Mónaco	5	2
		Á López Morón A Portas	4	4																		1	L Arnold M Hood	7	62	6
		D Bowen A Fisher	6																			WC	F Browne D Veronelli	5	77	4
		J Acasuso D Sánchez	4	r					D Bowen A Fisher	2	4
	WC	F Browne D Veronelli	6	77				WC	F Browne D Veronelli	6	6
	3	S Aspelin M Bertolini	2	62											WC	F Browne D Veronelli	2	7	6
		E Artoni A Schneiter	6												2	F Čermák L Friedl	6	5	4
		M Vassallo Argüello F Volandri	2	r					E Artoni A Schneiter	66	4
		N Lapentti M Rodríguez	4	2				2	F Čermák L Friedl	78	6
	2	F Čermák L Friedl	6	6

• ATP Buenos Aires Main Draw