2018 ASB Classic – Women's singles
2018 tennis event results
Lauren Davis was the defending champion, but lost in the first round to Sachia Vickery.
Julia Görges won the title, defeating Caroline Wozniacki in the final, 6–4, 7–6(7–4).
Wozniacki was in contention for the WTA No. 1 singles ranking at the start of the tournament. She was eliminated from contention when Simona Halep reached the quarterfinals in Shenzhen.[1]
Seeds
Draw
Finals
Top half
Bottom half
Qualifying
Seeds
Qualifiers
Qualifying draw
First qualifier
Second qualifier
Third qualifier
Fourth qualifier
References
External links
|
---|
Grand Slam events | |
---|
WTA Premier Mandatory tournaments | |
---|
WTA Premier 5 tournaments | |
---|
WTA Premier tournaments |
- Brisbane (S, D)
- Sydney (S, D)
- St. Petersburg (S, D)
- Dubai (S, D)
- Charleston (S, D)
- Stuttgart (S, D)
- Birmingham (S, D)
- Eastbourne (S, D)
- San Jose (S, D)
- New Haven (S, D)
- Tokyo (S, D)
- Moscow (S, D)
|
---|
WTA International tournaments |
- Auckland (S, D)
- Shenzhen (S, D)
- Hobart (S, D)
- Taipei (S, D)
- Budapest (S, D)
- Acapulco (S, D)
- Monterrey (S, D)
- Bogotá (S, D)
- Lugano (S, D)
- İstanbul (S, D)
- Prague (S, D)
- Rabat (S, D)
- Nuremberg (S, D)
- Strasbourg (S, D)
- Rosmalen (S, D)
- Nottingham (S, D)
- Santa Ponsa (S, D)
- Bucharest (S, D)
- Gstaad (S, D)
- Moscow (S, D)
- Nanchang (S, D)
- Washington D.C. (S, D)
- Hiroshima (S, D)
- Quebec City (S, D)
- Guangzhou (S, D)
- Seoul (S, D)
- Tashkent (S, D)
- Hong Kong (S, D)
- Linz (S, D)
- Tianjin (S, D)
- Luxembourg City (S, D)
|
---|
Team events | |
---|
|
|
|