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In elementary algebra, the AC method (also called the ac-grouping method or simply factoring by grouping) is a technique for factoring quadratic trinomials of the form

${\displaystyle ax^{2}+bx+c}$

1

where the leading coefficient ${\displaystyle a}$ is not equal to 1.^[1][2] The method is a systematic way of rewriting the middle term ${\displaystyle bx}$ as a sum of two terms whose coefficients have a product equal to ${\displaystyle ac}$ and a sum equal to ${\displaystyle b}$; the resulting four‑term polynomial is then factored by grouping.^[3][4]

The exact origins of the AC method are unclear, but it has been a standard fixture in American algebra textbooks since at least the late 20th century. The method is closely related to the technique of factoring by grouping, which appears in elementary algebra texts as early as the 19th century.^[3]

The name «AC method» derives from the first step of the process: computing the product ac (the product of the leading coefficient and the constant term).^[1] Some textbooks refer to it as the «ac‑grouping method» because it combines the multiplication step with the grouping technique.^[1]

The method became widely used in high school and college algebra curricula during the 1990s and 2000s as a systematic alternative to trial‑and‑error factoring.^[1][4][3][2]

The AC method is a systematic procedure for factoring quadratic trinomials of the form ${\displaystyle ax^{2}+bx+c}$ (with a ≠ 0) by transforming them into four‑term polynomials that can be factored by grouping.^[1][4]

The algorithm consists of the following steps:^[3][2]

• Compute the product ac, i.e., multiply the leading coefficient a by the constant term c.^[1]
• Find two integers p and q such that and p + q = b.^[3] If no such integers exist, the trinomial does not factor over the integers.^[2]
• Rewrite the middle term bx as the sum of two terms using p and q: ${\displaystyle bx=px+qx}$. The original trinomial becomes a four‑term polynomial: ${\displaystyle ax^{2}+px+qx+c}$.^[1]

Factor by grouping:

1. Group the first two terms and the last two terms: ${\displaystyle (ax^{2}+px)+(qx+c)}$;^[4]
2. Factor out the greatest common factor (GCF) from each group;
3. If the two groups contain a common binomial factor, factor it out to obtain the product of two binomials.^[4]

Verify the factorization by multiplying the binomials using the FOIL method; the result should equal the original trinomial.^[2]

The following example demonstrates the AC method.

Example. Factor ${\displaystyle 2x^{2}-11x+5}$

1. Identify the coefficients: a = 2, b = -11, c = 5;
2. Compute ${\displaystyle ac=2\times 5=10}$
3. Find two numbers whose product is 10 and whose sum is -11. The numbers -10 and -1 satisfy ${\displaystyle (-10)\times (-1)=10}$ and ${\displaystyle (-10)+(-1)=-11}$
4. Rewrite the middle term: ${\displaystyle 2x^{2}-10x-1x+5}$
5. Group: ${\displaystyle (2x^{2}-10x)+(-1x+5)}$
6. Factor each group: ${\displaystyle 2x(x-5)-1(x-5)}$
7. Factor out the common binomial (x - 5): ${\displaystyle (x-5)(2x-1)}$
8. Check by multiplication: ${\displaystyle (x-5)(2x-1)=2x^{2}-x-10x+5=2x^{2}-11x+5}$, which matches the original trinomial.

Thus, ${\displaystyle 2x^{2}-11x+5=(x-5)(2x-1)}$.

The following examples illustrate the application of the AC method in different situations.

Factor ${\displaystyle 2x^{2}+5x-12}$.^[1]

1. Identify the coefficients: a = 2, b = 5, c = -12
2. Compute ${\displaystyle ac=2\times (-12)=-24}$
3. Find two numbers whose product is -24 and whose sum is 5. The numbers 8 and -3 satisfy ${\displaystyle 8\times (-3)=-24}$ and ${\displaystyle 8+(-3)=5}$
4. Rewrite the middle term: ${\displaystyle 2x^{2}+8x-3x-12}$
5. Group: ${\displaystyle (2x^{2}+8x)+(-3x-12)}$
6. Factor each group: ${\displaystyle 2x(x+4)-3(x+4)}$
7. Factor out the common binomial (x + 4): ${\displaystyle (x+4)(2x-3)}$

Thus, ${\displaystyle 2x^{2}+5x-12=(x+4)(2x-3)}$.

Factor ${\displaystyle 4x^{2}-2x-6}$^[2]

1. First, factor out the greatest common factor (GCF) of all terms, which is 2: ${\displaystyle 4x^{2}-2x-6=2(2x^{2}-x-3)}$
2. Now factor the inner trinomial ${\displaystyle 2x^{2}-x-3}$ using the AC method
3. For ${\displaystyle 2x^{2}-x-3}$: a = 2, b = -1, c = -3
4. Compute ${\displaystyle ac=2\times (-3)=-6}$
5. Find two numbers whose product is -6 and whose sum is -1. The numbers -3 and 2 satisfy ${\displaystyle (-3)\times 2=-6}$ and ${\displaystyle (-3)+2=-1}$
6. Rewrite the middle term: ${\displaystyle 2x^{2}-3x+2x-3}$
7. Group: ${\displaystyle (2x^{2}-3x)+(2x-3)}$
8. Factor each group: ${\displaystyle x(2x-3)+1(2x-3)}$
9. Factor out the common binomial (2x - 3): ${\displaystyle (2x-3)(x+1)}$
10. Include the GCF factored out initially: ${\displaystyle 2(2x-3)(x+1)}$

Thus, ${\displaystyle 4x^{2}-2x-6=2(2x-3)(x+1)}$.

Factor ${\displaystyle x^{2}+x+1}$.^[3]

1. Identify the coefficients: a = 1, b = 1, c = 1
2. Compute ${\displaystyle ac=1\times 1=1}$
3. Find two integers whose product is 1 and whose sum is 1. The only integer pairs whose product is 1 are (1, 1) and (-1, -1). Their sums are 2 and -2 respectively, neither of which equals 1.
4. Since no such integers exist, the trinomial ${\displaystyle x^{2}+x+1}$ does not factor over the integers.^[2]

The AC method can be justified by examining the structure of a quadratic trinomial that factors over the integers. Suppose that the trinomial ${\displaystyle ax^{2}+bx+c}$ (with a ≠ 0) factors as

${\displaystyle ax^{2}+bx+c=(rx+s)(tx+u)}$

2

where r, s, t, u are integers and r ≠ 0, t ≠ 0. Expanding the right‑hand side gives

${\displaystyle ax^{2}+bx+c=(rt)x^{2}+(ru+st)x+(su).}$

3

From these relations, the product ac can be expressed as

${\displaystyle ac=(rt)(su)=(ru)(st).}$

5

Thus the two numbers ru and st have the following properties:

• Their product is ${\displaystyle ru\cdot st=(rt)(su)=ac}$;
• Their sum is ${\displaystyle ru+st=b}$.

These are precisely the two numbers p and q sought in the AC method: p = ru and q = st.^[3]

Once p and q are found, the original trinomial can be rewritten as

${\displaystyle ax^{2}+bx+c=ax^{2}+px+qx+c.}$

6

Substituting a = rt, p = ru, q = st, and c = su yields

${\displaystyle rtx^{2}+rux+stx+su.}$

7

Grouping the first two terms and the last two terms gives

${\displaystyle (rtx^{2}+rux)+(stx+su)=rx(tx+u)+s(tx+u)=(rx+s)(tx+u),}$

8

which is exactly the original factorization.^[1]

If no integers p and q satisfy pq = ac and p + q = b, then the trinomial cannot factor over the integers, as there would be no way to split the middle term to allow grouping into integer factors.^[2]

Several techniques exist for factoring quadratic trinomials. The AC method is one systematic approach; its strengths and weaknesses can be understood by comparing it to alternative methods.

• Trial and error (or guess and check) is the most basic method. The student attempts to find binomial factors ${\displaystyle (rx+s)(tx+u)}$ by testing combinations of integers r, t, s, u that satisfy rt = a and su = c, and then checks whether the resulting middle coefficient ru + st equals b.^[3] This method relies on intuition and can become tedious when a and c have many factor pairs. The AC method replaces guesswork with a systematic search for two numbers whose product is ac and sum is b, making it more reliable for students who struggle with trial and error.^[2]
• The quadratic formula provides a universal way to factor any quadratic polynomial over the real or complex numbers. If the equation ${\displaystyle ax^{2}+bx+c=0}$ has roots ${\displaystyle r_{1}}$ and ${\displaystyle r_{2}}$ (found by ${\displaystyle r={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}})}$, then the polynomial factors as ${\displaystyle a(x-r_{1})(x-r_{2})}$. This method always works, even when the roots are irrational or complex, but it requires computation of the discriminant and handling of radicals. For integer factorization, the quadratic formula is often more computationally heavy than necessary.^[1]
• The AC method is a specialized application of factoring by grouping. Grouping itself is a more general technique applicable to polynomials of any degree, but for a quadratic trinomial the AC method provides a concrete rule for splitting the middle term.^[1] Once the middle term is split, the remaining grouping step is identical to that used for higher‑degree polynomials.

The AC method has several limitations:^[2][3]

• It is designed specifically for quadratic trinomials of the form ${\displaystyle ax^{2}+bx+c}$. Polynomials of higher degree cannot be factored directly by this method unless they can be reduced to a quadratic through substitution.
• The method assumes that the coefficients a, b, c are integers (or can be made integers by factoring out a common denominator). If they are irrational, the search for integer p and q is meaningless.
• It works only when the trinomial factors over the integers. If the discriminant b^2 - 4ac is not a perfect square, no integers p, q with the required properties exist, and the method correctly indicates that the polynomial is prime over Z[x].^[2]
• For large values of ac, the enumeration of factor pairs can still be time‑consuming, although it is more systematic than random guessing. In such cases, the quadratic formula or computer algebra systems may be more efficient.