A total of eight women's teams qualified to compete at the games, four CONMEBOL teams and four CONCACAF teams.[1] For CONMEBOL, the three teams ranked third to fifth at the 2018 Copa América Femenina qualified, while Peru automatically qualified as hosts. For CONCACAF, the best team from each of the three zones (North American, Central American and Caribbean) at the 2018 CONCACAF Women's Championship qualified; however, both United States and Canada declined to participate to focus on the 2019 FIFA Women's World Cup, so Mexico qualified for the North American berth, while Costa Rica also qualified by decision of CONCACAF.[2]
The draw of the tournament was held on 12 April 2019, 12:00 PET (UTC−5), at the Peruvian Football Federation headquarters in Lima, Peru.[3][4] The eight teams were drawn into two groups of four and each group had two CONCACAF teams and two CONMEBOL teams. The hosts Peru were seeded into group B and assigned to position 4 in their group, while the remaining seven teams were placed into two pots according to the confederation to which they belong.
The CONCACAF teams were drawn first and assigned to positions 1 and 2 in groups A and B. Then, the CONMEBOL teams were drawn and the first two teams occupied positions 3 and 4 in group A while the third team occupied the position 3 in group B. The draw resulted in the following groups:[5]
