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The graph is not correct. For example the value for l=5, m=1, x=0 should be -15/8 but is around -0.32. — Preceding unsigned comment added by 129.16.35.40 (talk) 08:35, 30 April 2013 (UTC)Reply

I do not understand why the redirect is here. I can not seem to find the information that fits here on any other wikipedia site. The page which it redirects to is about a special case of the Legendre function. Neltah 15:51, 11 May 2007 (UTC)Reply

The definition for associated Legendre functions of the first and second kind are given for certain domains in ${\displaystyle z}$. There needs to be a discussion of how these functions are extended to other values of ${\displaystyle z}$ in the complex plane. HowiAuckland (talk) 14:12, 17 December 2010 (UTC)Reply

${\displaystyle Q_{\lambda }^{\mu }(z)={\frac {{\sqrt {\pi }}\ \Gamma (\lambda +\mu +1)}{2^{\lambda +1}\Gamma (\lambda +3/2)}}{\frac {e^{i\mu \pi }(z^{2}-1)^{\mu /2}}{z^{\lambda +\mu +1}}}\,_{2}F_{1}\left({\frac {\lambda +\mu +1}{2}},{\frac {\lambda +\mu +2}{2}};\lambda +{\frac {3}{2}};{\frac {1}{z^{2}}}\right),\qquad {\text{for}}\ \ |z|>1.}$

is different equation 8.820.2 in Gradshteyn, I. S., and I. M. Ryzhik, 2000, Table of integrals, series, and products, sixth ed.: Academic Press. (translated from the Russian).

and from equation 14.3.7 in Dunster, T. M., 2010, "Legendre and Related Functions" in "NIST Handbook of Mathematical Functions", Cambridge University Press.

which both state:

${\displaystyle Q_{\lambda }^{\mu }(z)={\frac {{\sqrt {\pi }}\ \Gamma (\lambda +\mu +1)}{2^{\lambda +1}\Gamma (\lambda +3/2)}}{\frac {e^{i\mu \pi }(z^{2}-1)^{\mu /2}}{z^{\lambda +\mu +1}}}\,_{2}F_{1}\left({\frac {\lambda +\mu +2}{2}},{\frac {\lambda +\mu +1}{2}};\lambda +{\frac {3}{2}};{\frac {1}{z^{2}}}\right),\qquad {\text{for}}\ \ |z|>1.}$

instead.

It should also be noted, that for \mu = 0, we receive the Legendre Functions. — Preceding unsigned comment added by 130.238.140.30 (talk) 16:33, 19 February 2013 (UTC)Reply

The Gauss hypergeometric function ${\displaystyle {}_{2}F_{1}(a,b;c;z)}$ does not change when the parameters ${\displaystyle a}$ and ${\displaystyle b}$ are interchanged. So these formulae are identical.HowiAuckland (talk) 19:34, 28 May 2013 (UTC)Reply

The section contains the sentence:"Like all such equations, it can be converted into the hypergeometric differential equation by a change of variable, and its solutions can be expressed using hypergeometric functions." This is obscure. Is this sentence referring to the general Legendre equation or second order linear equations or 2nd order linear DIFFERENTIAL equations (I don't have any idea what a 2nd order linear equation is, do you?) or is it referring to 2nd order linear (differential) equations with (3 ) singular points. "all such" is enormously sloppy and ambiguous. Also, imho the claim that ALL similar equations can be converted to hypergeometric DiffEQs requires, imho, a reference. That's three things, in case you're counting. (and if you include removing the "the" in front of 'the hypergeometric differential equation' that makes four. (This last I will change, being the one thing I'm confident enough of my understanding).173.189.72.93 (talk) 20:01, 17 November 2014 (UTC)Reply