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The following content was removed because it gives a misleading definition of pure shear. The definition is taken from an experimental paper where they get pure shear by constraining the upper and lower boundaries of a cube of material. Clearly, the following states cannot be pure shear in the general sense because the shear shows up in the off diagonal components of the deformation gradient, and the strain tensor. The linear elastic example given doesn't even include a shear strain component!

If ${\displaystyle \lambda }$ is the stretch ratio applied to the material, then the deformation gradient in pure shear can be expressed as^[1]

${\displaystyle {\boldsymbol {F}}={\begin{bmatrix}\lambda &0&0\\0&1&0\\0&0&1/\lambda \end{bmatrix}}.}$

The linear elastic stress-strain law for the case of pure shear is:

${\displaystyle {\begin{bmatrix}\sigma _{11}\\\sigma _{22}\\\sigma _{12}\end{bmatrix}}\,=\,{\begin{bmatrix}\sigma \\\nu \sigma \\0\end{bmatrix}}\,=\,{\frac {E}{1-\nu ^{2}}}{\begin{bmatrix}1&\nu &0\\\nu &1&0\\0&0&{\frac {1-\nu }{2}}\end{bmatrix}}{\begin{bmatrix}\varepsilon _{11}\\0\\0\end{bmatrix}}}$

The title of this article has various meanings in different sources. For instance, in 1998 Pavel Belik contributed "The State of Pure Shear" to the Journal of Elasticity (52(1):91-8), which states the following:

In classical continuum mechanics a state of pure shear is defined as one for which there is some orthonormal basis relative to which the normal components of the Cauchy stress tensor vanish. An equivalent characterization is that the trace of the Cauchy stress tensor must vanish.doi:10.1023/A:1007500316569

The articles on shear mapping and shear matrix have precise content compared to the title of this article.— Rgdboer (talk) 03:00, 1 December 2018 (UTC)Reply