The surface area of an augmented truncated tetrahedron is:[2]
the sum of the areas of its faces. Its volume can be calculated by slicing it off into both truncated tetrahedron and triangular cupola, and adding their volume:[2]
its dihedral angle between triangle and hexagon is as in the truncated tetrahedron: 109.47°;
its dihedral angle between adjacent hexagons is as in the truncated tetrahedron: 70.53°;
its dihedral angle between triangle and square is as in the triangular cupola's angle: 125.3°
its dihedral angle between triangle and square, on the edge where the triangular cupola and truncated tetrahedron are attached, is the sum of both triangular cupola's square-hexagon angle and the truncated tetrahedron's triangle-hexagon angle: approximately 164.17°; and
its dihedral angle between triangle and hexagon, on the edge where triangular cupola and truncated tetrahedron are attached, is the sum of the dihedral angle of a triangular cupola and truncated tetrahedron between that: approximately 141.3°;